If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12y^2+12y-24=0
a = 12; b = 12; c = -24;
Δ = b2-4ac
Δ = 122-4·12·(-24)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*12}=\frac{-48}{24} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*12}=\frac{24}{24} =1 $
| 2(2x-4)=13 | | 13(x-27)-43x=12 | | 6x39=13x | | 7y-5y-12=28.52 | | -0.72x+0.42x=6.9 | | -m+8=-6m-3m+8 | | 2x+23=x | | 36+4x=51+1.5 | | -20+12x=10x-18 | | 2(x−4)=6x+10 | | x-1.3333=5 | | 1+4r-5=-6+2r+r | | 3.56x+7.56x+9.12=50.86 | | 200m-75m+57300=60900-175m | | -7+n/4=-3 | | 16+(1/6)c=-3 | | 13=2(u+2)-5u | | 3(z+19)-1=14 | | 2x+3(x-7)=-4x-3 | | 4x+14+8x-14=90 | | 0.50m-1=0.25m+13 | | 1+1+3x+2x=6x+3 | | 1/3x=12+26 | | 3+3x-5x=17 | | -5=w+ | | p/2=p+1/6 | | -3x-14=x+8 | | 2x-1/2=1-2x/6 | | -0.51x+0.31x=5.4 | | 1/14n+6/17n=−4+4. | | -9t÷2=56 | | 27=-15x+27 |